Base | Representation |
---|---|
bin | 111101000000111100… |
… | …0001011000001101001 |
3 | 110112012120022022022221 |
4 | 1322001320023001221 |
5 | 4121321132124334 |
6 | 140105440514041 |
7 | 12315665444251 |
oct | 1720170130151 |
9 | 415176268287 |
10 | 131028004969 |
11 | 50628990514 |
12 | 2148901b921 |
13 | c481b688b4 |
14 | 64adc26961 |
15 | 361d2278b4 |
hex | 1e81e0b069 |
131028004969 has 2 divisors, whose sum is σ = 131028004970. Its totient is φ = 131028004968.
The previous prime is 131028004957. The next prime is 131028004979. The reversal of 131028004969 is 969400820131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101880979344 + 29147025625 = 319188^2 + 170725^2 .
It is a cyclic number.
It is not a de Polignac number, because 131028004969 - 213 = 131027996777 is a prime.
It is a super-2 number, since 2×1310280049692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131028004979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65514002484 + 65514002485.
It is an arithmetic number, because the mean of its divisors is an integer number (65514002485).
Almost surely, 2131028004969 is an apocalyptic number.
It is an amenable number.
131028004969 is a deficient number, since it is larger than the sum of its proper divisors (1).
131028004969 is an equidigital number, since it uses as much as digits as its factorization.
131028004969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 43.
The spelling of 131028004969 in words is "one hundred thirty-one billion, twenty-eight million, four thousand, nine hundred sixty-nine".
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