Base | Representation |
---|---|
bin | 10011000100010011111… |
… | …101111100010010110011 |
3 | 11122021010001200012022121 |
4 | 103010103331330102303 |
5 | 132431443301431011 |
6 | 2441535445015111 |
7 | 163444312326631 |
oct | 23042375742263 |
9 | 4567101605277 |
10 | 1310300030131 |
11 | 465771231294 |
12 | 191b409b4497 |
13 | 96739cc3321 |
14 | 475c14cc351 |
15 | 2413d2eae71 |
hex | 13113f7c4b3 |
1310300030131 has 2 divisors, whose sum is σ = 1310300030132. Its totient is φ = 1310300030130.
The previous prime is 1310300030087. The next prime is 1310300030147.
1310300030131 is nontrivially palindromic in base 10.
It is an a-pointer prime, because the next prime (1310300030147) can be obtained adding 1310300030131 to its sum of digits (16).
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 1310300030131 - 219 = 1310299505843 is a prime.
It is a super-2 number, since 2×13103000301312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310300030191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655150015065 + 655150015066.
It is an arithmetic number, because the mean of its divisors is an integer number (655150015066).
Almost surely, 21310300030131 is an apocalyptic number.
1310300030131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310300030131 is an equidigital number, since it uses as much as digits as its factorization.
1310300030131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 16.
It can be divided in two parts, 13103000 and 30131, that added together give a palindrome (13133131).
The spelling of 1310300030131 in words is "one trillion, three hundred ten billion, three hundred million, thirty thousand, one hundred thirty-one".
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