Base | Representation |
---|---|
bin | 1011111010101100011110… |
… | …1110111000110010100100 |
3 | 1201101122010200110010200212 |
4 | 2332223013232320302210 |
5 | 3204134421302210040 |
6 | 43511234033554552 |
7 | 2521442404422341 |
oct | 276530756706244 |
9 | 51348120403625 |
10 | 13103001210020 |
11 | 41a1a51652357 |
12 | 1577548715a58 |
13 | 7407b91b4077 |
14 | 33428d8c57c8 |
15 | 17ac8c103d65 |
hex | beac7bb8ca4 |
13103001210020 has 48 divisors (see below), whose sum is σ = 29137306489200. Its totient is φ = 4932488577024.
The previous prime is 13103001210017. The next prime is 13103001210023. The reversal of 13103001210020 is 2001210030131.
It is an interprime number because it is at equal distance from previous prime (13103001210017) and next prime (13103001210023).
It can be written as a sum of positive squares in 8 ways, for example, as 172303028836 + 12930698181184 = 415094^2 + 3595928^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13103001209977 and 13103001210004.
It is not an unprimeable number, because it can be changed into a prime (13103001210023) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2567156 + ... + 5726804.
It is an arithmetic number, because the mean of its divisors is an integer number (607027218525).
Almost surely, 213103001210020 is an apocalyptic number.
13103001210020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13103001210020 is an abundant number, since it is smaller than the sum of its proper divisors (16034305279180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13103001210020 is a wasteful number, since it uses less digits than its factorization.
13103001210020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3171872 (or 3171870 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 13103001210020 its reverse (2001210030131), we get a palindrome (15104211240151).
The spelling of 13103001210020 in words is "thirteen trillion, one hundred three billion, one million, two hundred ten thousand, twenty".
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