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1310302131223 is a prime number
BaseRepresentation
bin10011000100010100000…
…101111101010000010111
311122021010012121221110211
4103010110011331100113
5132431444321144343
62441540002030251
7163444336230361
oct23042405752027
94567105557424
101310302131223
11465772436928
12191b41648387
139673a57a787
14475c18b7d31
152413d5b379d
hex1311417d417

1310302131223 has 2 divisors, whose sum is σ = 1310302131224. Its totient is φ = 1310302131222.

The previous prime is 1310302131191. The next prime is 1310302131239. The reversal of 1310302131223 is 3221312030131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310302131223 - 25 = 1310302131191 is a prime.

It is a super-2 number, since 2×13103021312232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310302131194 and 1310302131203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310302131293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655151065611 + 655151065612.

It is an arithmetic number, because the mean of its divisors is an integer number (655151065612).

Almost surely, 21310302131223 is an apocalyptic number.

1310302131223 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310302131223 is an equidigital number, since it uses as much as digits as its factorization.

1310302131223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1310302131223 its reverse (3221312030131), we get a palindrome (4531614161354).

The spelling of 1310302131223 in words is "one trillion, three hundred ten billion, three hundred two million, one hundred thirty-one thousand, two hundred twenty-three".