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13103031312013 is a prime number
BaseRepresentation
bin1011111010101100100110…
…0001101101111010001101
31201101122012210002110212111
42332223021201231322031
53204140002003441023
643511241031104021
72521443221324266
oct276531141557215
951348183073774
1013103031312013
1141a1a67642435
121577556812011
137407c24c35b6
143342938bd96d
1517ac8ea9d00d
hexbeac986de8d

13103031312013 has 2 divisors, whose sum is σ = 13103031312014. Its totient is φ = 13103031312012.

The previous prime is 13103031311963. The next prime is 13103031312043. The reversal of 13103031312013 is 31021313030131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11132719384329 + 1970311927684 = 3336573^2 + 1403678^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13103031312013 is a prime.

It is a super-3 number, since 3×131030313120133 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13103031312043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551515656006 + 6551515656007.

It is an arithmetic number, because the mean of its divisors is an integer number (6551515656007).

Almost surely, 213103031312013 is an apocalyptic number.

It is an amenable number.

13103031312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103031312013 is an equidigital number, since it uses as much as digits as its factorization.

13103031312013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 13103031312013 its reverse (31021313030131), we get a palindrome (44124344342144).

The spelling of 13103031312013 in words is "thirteen trillion, one hundred three billion, thirty-one million, three hundred twelve thousand, thirteen".