Base | Representation |
---|---|
bin | 11101110010110000001001… |
… | …101010001001100010110101 |
3 | 122011221102222101010222102011 |
4 | 131302300021222021202311 |
5 | 114133303014210413303 |
6 | 1142402453243044221 |
7 | 36412451634561301 |
oct | 3562601152114265 |
9 | 564842871128364 |
10 | 131031024310453 |
11 | 38828a44284813 |
12 | 12842834b10671 |
13 | 58162321b5377 |
14 | 244dd14ac8d01 |
15 | 102363e81d16d |
hex | 772c09a898b5 |
131031024310453 has 2 divisors, whose sum is σ = 131031024310454. Its totient is φ = 131031024310452.
The previous prime is 131031024310423. The next prime is 131031024310493. The reversal of 131031024310453 is 354013420130131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 101742384348049 + 29288639962404 = 10086743^2 + 5411898^2 .
It is a cyclic number.
It is not a de Polignac number, because 131031024310453 - 25 = 131031024310421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131031024310423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515512155226 + 65515512155227.
It is an arithmetic number, because the mean of its divisors is an integer number (65515512155227).
Almost surely, 2131031024310453 is an apocalyptic number.
It is an amenable number.
131031024310453 is a deficient number, since it is larger than the sum of its proper divisors (1).
131031024310453 is an equidigital number, since it uses as much as digits as its factorization.
131031024310453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 131031024310453 its reverse (354013420130131), we get a palindrome (485044444440584).
The spelling of 131031024310453 in words is "one hundred thirty-one trillion, thirty-one billion, twenty-four million, three hundred ten thousand, four hundred fifty-three".
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