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131031024310453 is a prime number
BaseRepresentation
bin11101110010110000001001…
…101010001001100010110101
3122011221102222101010222102011
4131302300021222021202311
5114133303014210413303
61142402453243044221
736412451634561301
oct3562601152114265
9564842871128364
10131031024310453
1138828a44284813
1212842834b10671
1358162321b5377
14244dd14ac8d01
15102363e81d16d
hex772c09a898b5

131031024310453 has 2 divisors, whose sum is σ = 131031024310454. Its totient is φ = 131031024310452.

The previous prime is 131031024310423. The next prime is 131031024310493. The reversal of 131031024310453 is 354013420130131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101742384348049 + 29288639962404 = 10086743^2 + 5411898^2 .

It is a cyclic number.

It is not a de Polignac number, because 131031024310453 - 25 = 131031024310421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131031024310423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515512155226 + 65515512155227.

It is an arithmetic number, because the mean of its divisors is an integer number (65515512155227).

Almost surely, 2131031024310453 is an apocalyptic number.

It is an amenable number.

131031024310453 is a deficient number, since it is larger than the sum of its proper divisors (1).

131031024310453 is an equidigital number, since it uses as much as digits as its factorization.

131031024310453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 131031024310453 its reverse (354013420130131), we get a palindrome (485044444440584).

The spelling of 131031024310453 in words is "one hundred thirty-one trillion, thirty-one billion, twenty-four million, three hundred ten thousand, four hundred fifty-three".