Base | Representation |
---|---|
bin | 11101110010110000001010… |
… | …100111101100001101000011 |
3 | 122011221110000111111121101102 |
4 | 131302300022213230031003 |
5 | 114133303032323140303 |
6 | 1142402455020525015 |
7 | 36412452221652455 |
oct | 3562601247541503 |
9 | 564843014447342 |
10 | 131031040443203 |
11 | 38828a523a356a |
12 | 1284283a3b076b |
13 | 5816235643484 |
14 | 244dd16cc82d5 |
15 | 1023640e58288 |
hex | 772c0a9ec343 |
131031040443203 has 2 divisors, whose sum is σ = 131031040443204. Its totient is φ = 131031040443202.
The previous prime is 131031040443109. The next prime is 131031040443221. The reversal of 131031040443203 is 302344040130131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131031040443203 - 212 = 131031040439107 is a prime.
It is not a weakly prime, because it can be changed into another prime (131031040443253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515520221601 + 65515520221602.
It is an arithmetic number, because the mean of its divisors is an integer number (65515520221602).
Almost surely, 2131031040443203 is an apocalyptic number.
131031040443203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131031040443203 is an equidigital number, since it uses as much as digits as its factorization.
131031040443203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 131031040443203 its reverse (302344040130131), we get a palindrome (433375080573334).
The spelling of 131031040443203 in words is "one hundred thirty-one trillion, thirty-one billion, forty million, four hundred forty-three thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •