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13103113001112 = 233231139269315683
BaseRepresentation
bin1011111010101100111001…
…1001010101100010011000
31201101122102110210201020200
42332223032121111202120
53204140133412013422
643511253110022200
72521445232554031
oct276531631254230
951348373721220
1013103113001112
1141a1aa9767692
12157757a047960
137408063c5744
143342a06a5a88
1517ac96d372ac
hexbeace655898

13103113001112 has 192 divisors, whose sum is σ = 36911955225600. Its totient is φ = 4194576195840.

The previous prime is 13103113001107. The next prime is 13103113001117. The reversal of 13103113001112 is 21110031130131.

13103113001112 is a `hidden beast` number, since 1 + 31 + 0 + 311 + 300 + 11 + 12 = 666.

It is an interprime number because it is at equal distance from previous prime (13103113001107) and next prime (13103113001117).

It is a super-3 number, since 3×131031130011123 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13103113001117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 835490023 + ... + 835505705.

It is an arithmetic number, because the mean of its divisors is an integer number (192249766800).

Almost surely, 213103113001112 is an apocalyptic number.

13103113001112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13103113001112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18455977612800).

13103113001112 is an abundant number, since it is smaller than the sum of its proper divisors (23808842224488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13103113001112 is a wasteful number, since it uses less digits than its factorization.

13103113001112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18558 (or 18551 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 13103113001112 its reverse (21110031130131), we get a palindrome (34213144131243).

The spelling of 13103113001112 in words is "thirteen trillion, one hundred three billion, one hundred thirteen million, one thousand, one hundred twelve".