Base | Representation |
---|---|
bin | 111101000001000010… |
… | …0011010010001001100 |
3 | 110112012210100022002210 |
4 | 1322002010122101030 |
5 | 4121322442310012 |
6 | 140110033350420 |
7 | 12316034635431 |
oct | 1720204322114 |
9 | 415183308083 |
10 | 131031213132 |
11 | 5062a781896 |
12 | 2148a108410 |
13 | c48271cc11 |
14 | 64b041db88 |
15 | 361d65d23c |
hex | 1e8211a44c |
131031213132 has 12 divisors (see below), whose sum is σ = 305739497336. Its totient is φ = 43677071040.
The previous prime is 131031213119. The next prime is 131031213149. The reversal of 131031213132 is 231312130131.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 131031213099 and 131031213108.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5459633869 + ... + 5459633892.
Almost surely, 2131031213132 is an apocalyptic number.
131031213132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131031213132 is an abundant number, since it is smaller than the sum of its proper divisors (174708284204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131031213132 is a wasteful number, since it uses less digits than its factorization.
131031213132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10919267768 (or 10919267766 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 131031213132 its reverse (231312130131), we get a palindrome (362343343263).
The spelling of 131031213132 in words is "one hundred thirty-one billion, thirty-one million, two hundred thirteen thousand, one hundred thirty-two".
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