Search a number
-
+
131031213132 = 22310919267761
BaseRepresentation
bin111101000001000010…
…0011010010001001100
3110112012210100022002210
41322002010122101030
54121322442310012
6140110033350420
712316034635431
oct1720204322114
9415183308083
10131031213132
115062a781896
122148a108410
13c48271cc11
1464b041db88
15361d65d23c
hex1e8211a44c

131031213132 has 12 divisors (see below), whose sum is σ = 305739497336. Its totient is φ = 43677071040.

The previous prime is 131031213119. The next prime is 131031213149. The reversal of 131031213132 is 231312130131.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (12).

It is a junction number, because it is equal to n+sod(n) for n = 131031213099 and 131031213108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5459633869 + ... + 5459633892.

Almost surely, 2131031213132 is an apocalyptic number.

131031213132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131031213132 is an abundant number, since it is smaller than the sum of its proper divisors (174708284204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131031213132 is a wasteful number, since it uses less digits than its factorization.

131031213132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10919267768 (or 10919267766 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 131031213132 its reverse (231312130131), we get a palindrome (362343343263).

The spelling of 131031213132 in words is "one hundred thirty-one billion, thirty-one million, two hundred thirteen thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 10919267761 21838535522 32757803283 43677071044 65515606566 131031213132