Base | Representation |
---|---|
bin | 11101110010110000011010… |
… | …000110001111100001010100 |
3 | 122011221110200121010001211202 |
4 | 131302300122012033201110 |
5 | 114133304100312013140 |
6 | 1142402540454252032 |
7 | 36412461524046653 |
oct | 3562603206174124 |
9 | 564843617101752 |
10 | 131031300110420 |
11 | 38829075a2a376 |
12 | 128428b1357018 |
13 | 581627738c108 |
14 | 244dd3d59d19a |
15 | 1023658b4b915 |
hex | 772c1a18f854 |
131031300110420 has 12 divisors (see below), whose sum is σ = 275165730231924. Its totient is φ = 52412520044160.
The previous prime is 131031300110239. The next prime is 131031300110429. The reversal of 131031300110420 is 24011003130131.
It can be written as a sum of positive squares in 2 ways, for example, as 40468784034064 + 90562516076356 = 6361508^2 + 9516434^2 .
It is a Harshad number since it is a multiple of its sum of digits (20), and also a Moran number because the ratio is a prime number: 6551565005521 = 131031300110420 / (1 + 3 + 1 + 0 + 3 + 1 + 3 + 0 + 0 + 1 + 1 + 0 + 4 + 2 + 0).
It is a junction number, because it is equal to n+sod(n) for n = 131031300110392 and 131031300110401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131031300110429) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3275782502741 + ... + 3275782502780.
It is an arithmetic number, because the mean of its divisors is an integer number (22930477519327).
Almost surely, 2131031300110420 is an apocalyptic number.
131031300110420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131031300110420 is an abundant number, since it is smaller than the sum of its proper divisors (144134430121504).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131031300110420 is a wasteful number, since it uses less digits than its factorization.
131031300110420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6551565005530 (or 6551565005528 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 131031300110420 its reverse (24011003130131), we get a palindrome (155042303240551).
The spelling of 131031300110420 in words is "one hundred thirty-one trillion, thirty-one billion, three hundred million, one hundred ten thousand, four hundred twenty".
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