Base | Representation |
---|---|
bin | 10011000100010100101… |
… | …111100000001010010001 |
3 | 11122021010222010020221112 |
4 | 103010110233200022101 |
5 | 132432010113201342 |
6 | 2441541031303105 |
7 | 163444530630242 |
oct | 23042457401221 |
9 | 4567128106845 |
10 | 1310313022097 |
11 | 4657785a5352 |
12 | 191b4521aa95 |
13 | 9673c8c1991 |
14 | 475c3110cc9 |
15 | 2413e515682 |
hex | 13114be0291 |
1310313022097 has 2 divisors, whose sum is σ = 1310313022098. Its totient is φ = 1310313022096.
The previous prime is 1310313022079. The next prime is 1310313022121. The reversal of 1310313022097 is 7902203130131.
Together with previous prime (1310313022079) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1034907428416 + 275405593681 = 1017304^2 + 524791^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310313022097 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310313022597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655156511048 + 655156511049.
It is an arithmetic number, because the mean of its divisors is an integer number (655156511049).
Almost surely, 21310313022097 is an apocalyptic number.
It is an amenable number.
1310313022097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310313022097 is an equidigital number, since it uses as much as digits as its factorization.
1310313022097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 32.
The spelling of 1310313022097 in words is "one trillion, three hundred ten billion, three hundred thirteen million, twenty-two thousand, ninety-seven".
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