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1310313022097 is a prime number
BaseRepresentation
bin10011000100010100101…
…111100000001010010001
311122021010222010020221112
4103010110233200022101
5132432010113201342
62441541031303105
7163444530630242
oct23042457401221
94567128106845
101310313022097
114657785a5352
12191b4521aa95
139673c8c1991
14475c3110cc9
152413e515682
hex13114be0291

1310313022097 has 2 divisors, whose sum is σ = 1310313022098. Its totient is φ = 1310313022096.

The previous prime is 1310313022079. The next prime is 1310313022121. The reversal of 1310313022097 is 7902203130131.

Together with previous prime (1310313022079) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1034907428416 + 275405593681 = 1017304^2 + 524791^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310313022097 is a prime.

It is not a weakly prime, because it can be changed into another prime (1310313022597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655156511048 + 655156511049.

It is an arithmetic number, because the mean of its divisors is an integer number (655156511049).

Almost surely, 21310313022097 is an apocalyptic number.

It is an amenable number.

1310313022097 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310313022097 is an equidigital number, since it uses as much as digits as its factorization.

1310313022097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804, while the sum is 32.

The spelling of 1310313022097 in words is "one trillion, three hundred ten billion, three hundred thirteen million, twenty-two thousand, ninety-seven".