Base | Representation |
---|---|
bin | 10011000100010100101… |
… | …111100000001010101111 |
3 | 11122021010222010020222122 |
4 | 103010110233200022233 |
5 | 132432010113202002 |
6 | 2441541031303155 |
7 | 163444530630314 |
oct | 23042457401257 |
9 | 4567128106878 |
10 | 1310313022127 |
11 | 4657785a537a |
12 | 191b4521aabb |
13 | 9673c8c19b5 |
14 | 475c3110d0b |
15 | 2413e5156a2 |
hex | 13114be02af |
1310313022127 has 2 divisors, whose sum is σ = 1310313022128. Its totient is φ = 1310313022126.
The previous prime is 1310313022121. The next prime is 1310313022157. The reversal of 1310313022127 is 7212203130131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310313022127 - 212 = 1310313018031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310313022096 and 1310313022105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310313022121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655156511063 + 655156511064.
It is an arithmetic number, because the mean of its divisors is an integer number (655156511064).
Almost surely, 21310313022127 is an apocalyptic number.
1310313022127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310313022127 is an equidigital number, since it uses as much as digits as its factorization.
1310313022127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 1310313022127 its reverse (7212203130131), we get a palindrome (8522516152258).
The spelling of 1310313022127 in words is "one trillion, three hundred ten billion, three hundred thirteen million, twenty-two thousand, one hundred twenty-seven".
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