Base | Representation |
---|---|
bin | 11000011010000001… |
… | …00001000011110111 |
3 | 1020211011212112110122 |
4 | 30031000201003313 |
5 | 203313401003421 |
6 | 10004113442155 |
7 | 642464601404 |
oct | 141500410367 |
9 | 36734775418 |
10 | 13103141111 |
11 | 5614421945 |
12 | 265827035b |
13 | 130a875148 |
14 | 8c43372ab |
15 | 51a5272ab |
hex | 30d0210f7 |
13103141111 has 2 divisors, whose sum is σ = 13103141112. Its totient is φ = 13103141110.
The previous prime is 13103141069. The next prime is 13103141131. The reversal of 13103141111 is 11114130131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13103141111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13103141111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13103141131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551570555 + 6551570556.
It is an arithmetic number, because the mean of its divisors is an integer number (6551570556).
Almost surely, 213103141111 is an apocalyptic number.
13103141111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103141111 is an equidigital number, since it uses as much as digits as its factorization.
13103141111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 13103141111 its reverse (11114130131), we get a palindrome (24217271242).
The spelling of 13103141111 in words is "thirteen billion, one hundred three million, one hundred forty-one thousand, one hundred eleven".
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