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131031525511 is a prime number
BaseRepresentation
bin111101000001000010…
…1100110100010000111
3110112012210221011121101
41322002011212202013
54121323032304021
6140110044200531
712316040406235
oct1720205464207
9415183834541
10131031525511
115062a975557
122148a239147
13c4827cc163
1464b04a1955
15361d6c0a91
hex1e82166887

131031525511 has 2 divisors, whose sum is σ = 131031525512. Its totient is φ = 131031525510.

The previous prime is 131031525487. The next prime is 131031525517. The reversal of 131031525511 is 115525130131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131031525511 - 211 = 131031523463 is a prime.

It is a super-2 number, since 2×1310315255112 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131031525511.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131031525517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515762755 + 65515762756.

It is an arithmetic number, because the mean of its divisors is an integer number (65515762756).

Almost surely, 2131031525511 is an apocalyptic number.

131031525511 is a deficient number, since it is larger than the sum of its proper divisors (1).

131031525511 is an equidigital number, since it uses as much as digits as its factorization.

131031525511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2250, while the sum is 28.

Adding to 131031525511 its reverse (115525130131), we get a palindrome (246556655642).

The spelling of 131031525511 in words is "one hundred thirty-one billion, thirty-one million, five hundred twenty-five thousand, five hundred eleven".