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13103200000141 is a prime number
BaseRepresentation
bin1011111010101101001110…
…0101001101100010001101
31201101122122112111201110221
42332223103211031202031
53204140323200001031
643511305454431341
72521450340210356
oct276532345154215
951348575451427
1013103200000141
1141a2043889309
1215775a3202551
1374081b436764
143342ac070d2d
1517ac9e7bea11
hexbead394d88d

13103200000141 has 2 divisors, whose sum is σ = 13103200000142. Its totient is φ = 13103200000140.

The previous prime is 13103200000031. The next prime is 13103200000147. The reversal of 13103200000141 is 14100000230131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12383325810025 + 719874190116 = 3518995^2 + 848454^2 .

It is a cyclic number.

It is not a de Polignac number, because 13103200000141 - 29 = 13103199999629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13103200000147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551600000070 + 6551600000071.

It is an arithmetic number, because the mean of its divisors is an integer number (6551600000071).

Almost surely, 213103200000141 is an apocalyptic number.

It is an amenable number.

13103200000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103200000141 is an equidigital number, since it uses as much as digits as its factorization.

13103200000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13103200000141 its reverse (14100000230131), we get a palindrome (27203200230272).

The spelling of 13103200000141 in words is "thirteen trillion, one hundred three billion, two hundred million, one hundred forty-one", and thus it is an aban number.