Base | Representation |
---|---|
bin | 111101000001000100… |
… | …0001101101000111001 |
3 | 110112012212012221111222 |
4 | 1322002020031220321 |
5 | 4121323221204402 |
6 | 140110111001425 |
7 | 12316046256614 |
oct | 1720210155071 |
9 | 415185187458 |
10 | 131032209977 |
11 | 506302a2829 |
12 | 2148a509275 |
13 | c4829ab876 |
14 | 64b05dd17b |
15 | 361d7a87a2 |
hex | 1e8220da39 |
131032209977 has 2 divisors, whose sum is σ = 131032209978. Its totient is φ = 131032209976.
The previous prime is 131032209941. The next prime is 131032210021. The reversal of 131032209977 is 779902230131.
It is an a-pointer prime, because the next prime (131032210021) can be obtained adding 131032209977 to its sum of digits (44).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 101057866816 + 29974343161 = 317896^2 + 173131^2 .
It is a cyclic number.
It is not a de Polignac number, because 131032209977 - 224 = 131015432761 is a prime.
It is not a weakly prime, because it can be changed into another prime (131032209907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65516104988 + 65516104989.
It is an arithmetic number, because the mean of its divisors is an integer number (65516104989).
Almost surely, 2131032209977 is an apocalyptic number.
It is an amenable number.
131032209977 is a deficient number, since it is larger than the sum of its proper divisors (1).
131032209977 is an equidigital number, since it uses as much as digits as its factorization.
131032209977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 142884, while the sum is 44.
The spelling of 131032209977 in words is "one hundred thirty-one billion, thirty-two million, two hundred nine thousand, nine hundred seventy-seven".
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