131033011121320 has 128 divisors (see below), whose sum is σ = 376538320569600. Its totient is φ = 39845324851200.

The previous prime is 131033011121291. The next prime is 131033011121359. The reversal of 131033011121320 is 23121110330131.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 131033011121291 and 131033011121300.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 518693055 + ... + 518945614.

It is an arithmetic number, because the mean of its divisors is an integer number (2941705629450).

Almost surely, 2^{131033011121320} is an apocalyptic number.

131033011121320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131033011121320 is an abundant number, since it is smaller than the sum of its proper divisors (245505309448280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131033011121320 is a wasteful number, since it uses less digits than its factorization.

131033011121320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1037638739 (or 1037638735 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 131033011121320 its reverse (23121110330131), we get a palindrome (154154121451451).

The spelling of 131033011121320 in words is "one hundred thirty-one trillion, thirty-three billion, eleven million, one hundred twenty-one thousand, three hundred twenty".