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131033426099 is a prime number
BaseRepresentation
bin111101000001000110…
…0110110100010110011
3110112012221111201201112
41322002030312202303
54121324024113344
6140110153023535
712316062513302
oct1720214664263
9415187451645
10131033426099
1150630a53494
122148a9b4bab
13c483016274
1464b0838439
15361d948c9e
hex1e823368b3

131033426099 has 2 divisors, whose sum is σ = 131033426100. Its totient is φ = 131033426098.

The previous prime is 131033426057. The next prime is 131033426101. The reversal of 131033426099 is 990624330131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131033426099 is a prime.

Together with 131033426101, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131033426009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65516713049 + 65516713050.

It is an arithmetic number, because the mean of its divisors is an integer number (65516713050).

Almost surely, 2131033426099 is an apocalyptic number.

131033426099 is a deficient number, since it is larger than the sum of its proper divisors (1).

131033426099 is an equidigital number, since it uses as much as digits as its factorization.

131033426099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 104976, while the sum is 41.

The spelling of 131033426099 in words is "one hundred thirty-one billion, thirty-three million, four hundred twenty-six thousand, ninety-nine".