Base | Representation |
---|---|
bin | 11000011010000011… |
… | …00000010111110001 |
3 | 1020211012100201012011 |
4 | 30031001200113301 |
5 | 203313432303213 |
6 | 10004123202521 |
7 | 642500031424 |
oct | 141501402761 |
9 | 36735321164 |
10 | 13103400433 |
11 | 5614589762 |
12 | 2658376441 |
13 | 130a9361a6 |
14 | 8c43a39bb |
15 | 51a57903d |
hex | 30d0605f1 |
13103400433 has 2 divisors, whose sum is σ = 13103400434. Its totient is φ = 13103400432.
The previous prime is 13103400413. The next prime is 13103400439. The reversal of 13103400433 is 33400430131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9543726864 + 3559673569 = 97692^2 + 59663^2 .
It is an emirp because it is prime and its reverse (33400430131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13103400433 - 213 = 13103392241 is a prime.
It is not a weakly prime, because it can be changed into another prime (13103400439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551700216 + 6551700217.
It is an arithmetic number, because the mean of its divisors is an integer number (6551700217).
Almost surely, 213103400433 is an apocalyptic number.
It is an amenable number.
13103400433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103400433 is an equidigital number, since it uses as much as digits as its factorization.
13103400433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 13103400433 its reverse (33400430131), we get a palindrome (46503830564).
The spelling of 13103400433 in words is "thirteen billion, one hundred three million, four hundred thousand, four hundred thirty-three".
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