Base | Representation |
---|---|
bin | 111101000001000111… |
… | …1001011000010100111 |
3 | 110112012222122122002002 |
4 | 1322002033023002213 |
5 | 4121324203044333 |
6 | 140110214035515 |
7 | 12316100625512 |
oct | 1720217130247 |
9 | 415188578062 |
10 | 131034034343 |
11 | 50631329473 |
12 | 2148b048b9b |
13 | c48319a084 |
14 | 64b0955d79 |
15 | 361da190e8 |
hex | 1e823cb0a7 |
131034034343 has 2 divisors, whose sum is σ = 131034034344. Its totient is φ = 131034034342.
The previous prime is 131034034297. The next prime is 131034034387. The reversal of 131034034343 is 343430430131.
It is a strong prime.
It is an emirp because it is prime and its reverse (343430430131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131034034343 - 26 = 131034034279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131034034843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65517017171 + 65517017172.
It is an arithmetic number, because the mean of its divisors is an integer number (65517017172).
Almost surely, 2131034034343 is an apocalyptic number.
131034034343 is a deficient number, since it is larger than the sum of its proper divisors (1).
131034034343 is an equidigital number, since it uses as much as digits as its factorization.
131034034343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 131034034343 its reverse (343430430131), we get a palindrome (474464464474).
The spelling of 131034034343 in words is "one hundred thirty-one billion, thirty-four million, thirty-four thousand, three hundred forty-three".
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