Base | Representation |
---|---|
bin | 11101110010110011000011… |
… | …100110110111000000000001 |
3 | 122011221202000210102010222202 |
4 | 131302303003212313000001 |
5 | 114133330411331311431 |
6 | 1142404131005042545 |
7 | 36412622145565043 |
oct | 3562630346670001 |
9 | 564852023363882 |
10 | 131034144010241 |
11 | 3882a2a52713aa |
12 | 12843365856455 |
13 | 581660b619c84 |
14 | 245012d16da93 |
15 | 10237736588cb |
hex | 772cc39b7001 |
131034144010241 has 2 divisors, whose sum is σ = 131034144010242. Its totient is φ = 131034144010240.
The previous prime is 131034144010223. The next prime is 131034144010247. The reversal of 131034144010241 is 142010441430131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127211239209616 + 3822904800625 = 11278796^2 + 1955225^2 .
It is a cyclic number.
It is not a de Polignac number, because 131034144010241 - 246 = 60665399832577 is a prime.
It is not a weakly prime, because it can be changed into another prime (131034144010247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65517072005120 + 65517072005121.
It is an arithmetic number, because the mean of its divisors is an integer number (65517072005121).
Almost surely, 2131034144010241 is an apocalyptic number.
It is an amenable number.
131034144010241 is a deficient number, since it is larger than the sum of its proper divisors (1).
131034144010241 is an equidigital number, since it uses as much as digits as its factorization.
131034144010241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 131034144010241 its reverse (142010441430131), we get a palindrome (273044585440372).
The spelling of 131034144010241 in words is "one hundred thirty-one trillion, thirty-four billion, one hundred forty-four million, ten thousand, two hundred forty-one".
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