Base | Representation |
---|---|
bin | 10011000100010110100… |
… | …110011110111110110011 |
3 | 11122021020010210220000001 |
4 | 103010112212132332303 |
5 | 132432041104244103 |
6 | 2441544104010431 |
7 | 163445360014132 |
oct | 23042646367663 |
9 | 4567203726001 |
10 | 1310344212403 |
11 | 465794169066 |
12 | 191b53760a17 |
13 | 967461c2695 |
14 | 475c730d919 |
15 | 2414212701d |
hex | 1311699efb3 |
1310344212403 has 2 divisors, whose sum is σ = 1310344212404. Its totient is φ = 1310344212402.
The previous prime is 1310344212383. The next prime is 1310344212449. The reversal of 1310344212403 is 3042124430131.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (3042124430131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310344212403 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310344212493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655172106201 + 655172106202.
It is an arithmetic number, because the mean of its divisors is an integer number (655172106202).
Almost surely, 21310344212403 is an apocalyptic number.
1310344212403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310344212403 is an equidigital number, since it uses as much as digits as its factorization.
1310344212403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1310344212403 its reverse (3042124430131), we get a palindrome (4352468642534).
The spelling of 1310344212403 in words is "one trillion, three hundred ten billion, three hundred forty-four million, two hundred twelve thousand, four hundred three".
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