Base | Representation |
---|---|
bin | 10011000100010110111… |
… | …101101110001111101010 |
3 | 11122021020120021101102102 |
4 | 103010112331232033222 |
5 | 132432044134213414 |
6 | 2441544442333402 |
7 | 163445462545436 |
oct | 23042675561752 |
9 | 4567216241372 |
10 | 1310350304234 |
11 | 465797649a34 |
12 | 191b557ba262 |
13 | 9674754640a |
14 | 475c80579c6 |
15 | 2414292bede |
hex | 13116f6e3ea |
1310350304234 has 32 divisors (see below), whose sum is σ = 2174461632000. Its totient is φ = 589434311664.
The previous prime is 1310350304213. The next prime is 1310350304261. The reversal of 1310350304234 is 4324030530131.
It is a super-2 number, since 2×13103503042342 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1310350304197 and 1310350304206.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5271524 + ... + 5514495.
It is an arithmetic number, because the mean of its divisors is an integer number (67951926000).
Almost surely, 21310350304234 is an apocalyptic number.
1310350304234 is a deficient number, since it is larger than the sum of its proper divisors (864111327766).
1310350304234 is a wasteful number, since it uses less digits than its factorization.
1310350304234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10786202.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 1310350304234 its reverse (4324030530131), we get a palindrome (5634380834365).
The spelling of 1310350304234 in words is "one trillion, three hundred ten billion, three hundred fifty million, three hundred four thousand, two hundred thirty-four".
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