Base | Representation |
---|---|
bin | 10011000100010111000… |
… | …110000111001001100001 |
3 | 11122021020201102010002202 |
4 | 103010113012013021201 |
5 | 132432100220102033 |
6 | 2441545001422545 |
7 | 163445520335123 |
oct | 23042706071141 |
9 | 4567221363082 |
10 | 1310352503393 |
11 | 46579891121a |
12 | 191b5649aa55 |
13 | 96747b363ab |
14 | 475c846b213 |
15 | 24142c138e8 |
hex | 13117187261 |
1310352503393 has 2 divisors, whose sum is σ = 1310352503394. Its totient is φ = 1310352503392.
The previous prime is 1310352503311. The next prime is 1310352503399. The reversal of 1310352503393 is 3933052530131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1306227267409 + 4125235984 = 1142903^2 + 64228^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310352503393 - 210 = 1310352502369 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310352503399) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655176251696 + 655176251697.
It is an arithmetic number, because the mean of its divisors is an integer number (655176251697).
Almost surely, 21310352503393 is an apocalyptic number.
It is an amenable number.
1310352503393 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310352503393 is an equidigital number, since it uses as much as digits as its factorization.
1310352503393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 109350, while the sum is 38.
The spelling of 1310352503393 in words is "one trillion, three hundred ten billion, three hundred fifty-two million, five hundred three thousand, three hundred ninety-three".
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