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1310354430557 is a prime number
BaseRepresentation
bin10011000100010111001…
…101011101101001011101
311122021020212001000200012
4103010113031131221131
5132432101213234212
62441545111013005
7163445542612514
oct23042715355135
94567225030605
101310354430557
11465799a08117
12191b5706a165
139674835c623
14475c880d67b
1524142e94922
hex1311735da5d

1310354430557 has 2 divisors, whose sum is σ = 1310354430558. Its totient is φ = 1310354430556.

The previous prime is 1310354430439. The next prime is 1310354430577. The reversal of 1310354430557 is 7550344530131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 714750194041 + 595604236516 = 845429^2 + 771754^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310354430557 - 212 = 1310354426461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310354430577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655177215278 + 655177215279.

It is an arithmetic number, because the mean of its divisors is an integer number (655177215279).

Almost surely, 21310354430557 is an apocalyptic number.

It is an amenable number.

1310354430557 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310354430557 is an equidigital number, since it uses as much as digits as its factorization.

1310354430557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378000, while the sum is 41.

Adding to 1310354430557 its reverse (7550344530131), we get a palindrome (8860698960688).

The spelling of 1310354430557 in words is "one trillion, three hundred ten billion, three hundred fifty-four million, four hundred thirty thousand, five hundred fifty-seven".