Base | Representation |
---|---|
bin | 10011000100010111001… |
… | …101011101101001011101 |
3 | 11122021020212001000200012 |
4 | 103010113031131221131 |
5 | 132432101213234212 |
6 | 2441545111013005 |
7 | 163445542612514 |
oct | 23042715355135 |
9 | 4567225030605 |
10 | 1310354430557 |
11 | 465799a08117 |
12 | 191b5706a165 |
13 | 9674835c623 |
14 | 475c880d67b |
15 | 24142e94922 |
hex | 1311735da5d |
1310354430557 has 2 divisors, whose sum is σ = 1310354430558. Its totient is φ = 1310354430556.
The previous prime is 1310354430439. The next prime is 1310354430577. The reversal of 1310354430557 is 7550344530131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 714750194041 + 595604236516 = 845429^2 + 771754^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310354430557 - 212 = 1310354426461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310354430577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655177215278 + 655177215279.
It is an arithmetic number, because the mean of its divisors is an integer number (655177215279).
Almost surely, 21310354430557 is an apocalyptic number.
It is an amenable number.
1310354430557 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310354430557 is an equidigital number, since it uses as much as digits as its factorization.
1310354430557 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378000, while the sum is 41.
Adding to 1310354430557 its reverse (7550344530131), we get a palindrome (8860698960688).
The spelling of 1310354430557 in words is "one trillion, three hundred ten billion, three hundred fifty-four million, four hundred thirty thousand, five hundred fifty-seven".
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