Base | Representation |
---|---|
bin | 10011000100010111010… |
… | …000000110011101100111 |
3 | 11122021020220100011012001 |
4 | 103010113100012131213 |
5 | 132432101402401043 |
6 | 2441545133510131 |
7 | 163445551522453 |
oct | 23042720063547 |
9 | 4567226304161 |
10 | 1310355122023 |
11 | 46579a33a682 |
12 | 191b57342347 |
13 | 9674854228c |
14 | 475c894d663 |
15 | 2414307e74d |
hex | 13117406767 |
1310355122023 has 2 divisors, whose sum is σ = 1310355122024. Its totient is φ = 1310355122022.
The previous prime is 1310355122017. The next prime is 1310355122039. The reversal of 1310355122023 is 3202215530131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310355122023 - 29 = 1310355121511 is a prime.
It is a super-2 number, since 2×13103551220232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1310355121982 and 1310355122000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310355122093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655177561011 + 655177561012.
It is an arithmetic number, because the mean of its divisors is an integer number (655177561012).
Almost surely, 21310355122023 is an apocalyptic number.
1310355122023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310355122023 is an equidigital number, since it uses as much as digits as its factorization.
1310355122023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 28.
The spelling of 1310355122023 in words is "one trillion, three hundred ten billion, three hundred fifty-five million, one hundred twenty-two thousand, twenty-three".
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