Base | Representation |
---|---|
bin | 1011111010101110100011… |
… | …0000010100011100000101 |
3 | 1201101200120021221110002112 |
4 | 2332223220300110130011 |
5 | 3204142040114433131 |
6 | 43511405024350405 |
7 | 2521462212512303 |
oct | 276535060243405 |
9 | 51350507843075 |
10 | 13103555233541 |
11 | 41a2206358433 |
12 | 1577682175405 |
13 | 740876c02a36 |
14 | 334303301273 |
15 | 17acc0a8e02b |
hex | beae8c14705 |
13103555233541 has 2 divisors, whose sum is σ = 13103555233542. Its totient is φ = 13103555233540.
The previous prime is 13103555233519. The next prime is 13103555233553. The reversal of 13103555233541 is 14533255530131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12821025777316 + 282529456225 = 3580646^2 + 531535^2 .
It is a cyclic number.
It is not a de Polignac number, because 13103555233541 - 210 = 13103555232517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13103555293541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551777616770 + 6551777616771.
It is an arithmetic number, because the mean of its divisors is an integer number (6551777616771).
Almost surely, 213103555233541 is an apocalyptic number.
It is an amenable number.
13103555233541 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103555233541 is an equidigital number, since it uses as much as digits as its factorization.
13103555233541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 405000, while the sum is 41.
The spelling of 13103555233541 in words is "thirteen trillion, one hundred three billion, five hundred fifty-five million, two hundred thirty-three thousand, five hundred forty-one".
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