Base | Representation |
---|---|
bin | 11000011010000111… |
… | …10010110011000011 |
3 | 1020211020111011220120 |
4 | 30031003302303003 |
5 | 203314111001240 |
6 | 10004144111323 |
7 | 642505110126 |
oct | 141503626303 |
9 | 36736434816 |
10 | 13104000195 |
11 | 5614959330 |
12 | 2658605543 |
13 | 130aab6190 |
14 | 8c44bc3bd |
15 | 51a646ad0 |
hex | 30d0f2cc3 |
13104000195 has 64 divisors (see below), whose sum is σ = 24770188800. Its totient is φ = 5831792640.
The previous prime is 13104000187. The next prime is 13104000223. The reversal of 13104000195 is 59100040131.
It is not a de Polignac number, because 13104000195 - 23 = 13104000187 is a prime.
It is a super-2 number, since 2×131040001952 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 366891 + ... + 401019.
It is an arithmetic number, because the mean of its divisors is an integer number (387034200).
Almost surely, 213104000195 is an apocalyptic number.
13104000195 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13104000195 is a deficient number, since it is larger than the sum of its proper divisors (11666188605).
13104000195 is a wasteful number, since it uses less digits than its factorization.
13104000195 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34340.
The product of its (nonzero) digits is 540, while the sum is 24.
The spelling of 13104000195 in words is "thirteen billion, one hundred four million, one hundred ninety-five", and thus it is an aban number.
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