Base | Representation |
---|---|
bin | 11000011010000111… |
… | …10101011100001001 |
3 | 1020211020111201202101 |
4 | 30031003311130021 |
5 | 203314111323032 |
6 | 10004144233401 |
7 | 642505153516 |
oct | 141503653411 |
9 | 36736451671 |
10 | 13104011017 |
11 | 5614966479 |
12 | 265860b861 |
13 | 130aabb096 |
14 | 8c44c230d |
15 | 51a649de7 |
hex | 30d0f5709 |
13104011017 has 2 divisors, whose sum is σ = 13104011018. Its totient is φ = 13104011016.
The previous prime is 13104010993. The next prime is 13104011027. The reversal of 13104011017 is 71011040131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12459917376 + 644093641 = 111624^2 + 25379^2 .
It is an emirp because it is prime and its reverse (71011040131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13104011017 - 215 = 13103978249 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13104010985 and 13104011003.
It is not a weakly prime, because it can be changed into another prime (13104011027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552005508 + 6552005509.
It is an arithmetic number, because the mean of its divisors is an integer number (6552005509).
Almost surely, 213104011017 is an apocalyptic number.
It is an amenable number.
13104011017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104011017 is an equidigital number, since it uses as much as digits as its factorization.
13104011017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 13104011017 its reverse (71011040131), we get a palindrome (84115051148).
The spelling of 13104011017 in words is "thirteen billion, one hundred four million, eleven thousand, seventeen".
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