13104031204233 has 24 divisors (see below), whose sum is σ = 18969253380168. Its totient is φ = 8717022150912.

The previous prime is 13104031204223. The next prime is 13104031204247. The reversal of 13104031204233 is 33240213040131.

It is a happy number.

13104031204233 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 403 + 1 + 20 + 4 + 233 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 522169547769 + 12581861656464 = 722613^2 + 3547092^2 .

It is a de Polignac number, because none of the positive numbers 2^k-13104031204233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104031204197 and 13104031204206.

It is not an unprimeable number, because it can be changed into a prime (13104031204223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6797941 + ... + 8509997.

It is an arithmetic number, because the mean of its divisors is an integer number (790385557507).

Almost surely, 2^{13104031204233} is an apocalyptic number.

It is an amenable number.

13104031204233 is a deficient number, since it is larger than the sum of its proper divisors (5865222175935).

13104031204233 is a wasteful number, since it uses less digits than its factorization.

13104031204233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1713913 (or 1713910 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 13104031204233 its reverse (33240213040131), we get a palindrome (46344244244364).

The spelling of 13104031204233 in words is "thirteen trillion, one hundred four billion, thirty-one million, two hundred four thousand, two hundred thirty-three".