Base | Representation |
---|---|
bin | 1011111010110000010111… |
… | …0010101110010110101001 |
3 | 1201101201211020122020021202 |
4 | 2332230011302232112221 |
5 | 3204144034323400431 |
6 | 43511525230213545 |
7 | 2521510246421156 |
oct | 276540562562651 |
9 | 51351736566252 |
10 | 13104042403241 |
11 | 41a2436351219 |
12 | 15777993542b5 |
13 | 740923b14c2a |
14 | 33434bcb722d |
15 | 17aced7208cb |
hex | beb05cae5a9 |
13104042403241 has 2 divisors, whose sum is σ = 13104042403242. Its totient is φ = 13104042403240.
The previous prime is 13104042403229. The next prime is 13104042403253. The reversal of 13104042403241 is 14230424040131.
It is a balanced prime because it is at equal distance from previous prime (13104042403229) and next prime (13104042403253).
It can be written as a sum of positive squares in only one way, i.e., 11109722265625 + 1994320137616 = 3333125^2 + 1412204^2 .
It is a cyclic number.
It is not a de Polignac number, because 13104042403241 - 238 = 12829164496297 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104042403261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552021201620 + 6552021201621.
It is an arithmetic number, because the mean of its divisors is an integer number (6552021201621).
Almost surely, 213104042403241 is an apocalyptic number.
It is an amenable number.
13104042403241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104042403241 is an equidigital number, since it uses as much as digits as its factorization.
13104042403241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 13104042403241 its reverse (14230424040131), we get a palindrome (27334466443372).
The spelling of 13104042403241 in words is "thirteen trillion, one hundred four billion, forty-two million, four hundred three thousand, two hundred forty-one".
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