Base | Representation |
---|---|
bin | 1011111010110000010111… |
… | …0101110110101111000000 |
3 | 1201101201211022011221011020 |
4 | 2332230011311312233000 |
5 | 3204144040031132000 |
6 | 43511525255545440 |
7 | 2521510256410101 |
oct | 276540565665700 |
9 | 51351738157136 |
10 | 13104043224000 |
11 | 41a2436861933 |
12 | 157779968b280 |
13 | 7409240416a1 |
14 | 33434c04c3a8 |
15 | 17aced833ba0 |
hex | beb05d76bc0 |
13104043224000 has 224 divisors, whose sum is σ = 45814819841856. Its totient is φ = 3288857804800.
The previous prime is 13104043223939. The next prime is 13104043224007. The reversal of 13104043224000 is 42234040131.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104043224007) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15650877 + ... + 16466876.
Almost surely, 213104043224000 is an apocalyptic number.
13104043224000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13104043224000 is an abundant number, since it is smaller than the sum of its proper divisors (32710776617856).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13104043224000 is a wasteful number, since it uses less digits than its factorization.
13104043224000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32117800 (or 32117780 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 13104043224000 its reverse (42234040131), we get a palindrome (13146277264131).
The spelling of 13104043224000 in words is "thirteen trillion, one hundred four billion, forty-three million, two hundred twenty-four thousand".
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