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131040452143 is a prime number
BaseRepresentation
bin111101000001010011…
…1101001111000101111
3110112020102201200122101
41322002213221320233
54121332323432033
6140111003355531
712316206315346
oct1720247517057
9415212650571
10131040452143
1150634a12237
1221491222ba7
13c4846062a3
1464b1746b5d
15361e38597d
hex1e829e9e2f

131040452143 has 2 divisors, whose sum is σ = 131040452144. Its totient is φ = 131040452142.

The previous prime is 131040452009. The next prime is 131040452173. The reversal of 131040452143 is 341254040131.

It is a strong prime.

It is an emirp because it is prime and its reverse (341254040131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131040452143 - 213 = 131040443951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131040452173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65520226071 + 65520226072.

It is an arithmetic number, because the mean of its divisors is an integer number (65520226072).

Almost surely, 2131040452143 is an apocalyptic number.

131040452143 is a deficient number, since it is larger than the sum of its proper divisors (1).

131040452143 is an equidigital number, since it uses as much as digits as its factorization.

131040452143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 131040452143 its reverse (341254040131), we get a palindrome (472294492274).

The spelling of 131040452143 in words is "one hundred thirty-one billion, forty million, four hundred fifty-two thousand, one hundred forty-three".