Base | Representation |
---|---|
bin | 11000011010001000… |
… | …01011110000010101 |
3 | 1020211020200101010201 |
4 | 30031010023300111 |
5 | 203314122234141 |
6 | 10004150220501 |
7 | 642506014144 |
oct | 141504136025 |
9 | 36736611121 |
10 | 13104102421 |
11 | 5614a19113 |
12 | 2658654731 |
13 | 130ab20877 |
14 | 8c450775b |
15 | 51a667031 |
hex | 30d10bc15 |
13104102421 has 2 divisors, whose sum is σ = 13104102422. Its totient is φ = 13104102420.
The previous prime is 13104102397. The next prime is 13104102437. The reversal of 13104102421 is 12420140131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13021092100 + 83010321 = 114110^2 + 9111^2 .
It is a cyclic number.
It is not a de Polignac number, because 13104102421 - 27 = 13104102293 is a prime.
It is a super-2 number, since 2×131041024212 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104132421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552051210 + 6552051211.
It is an arithmetic number, because the mean of its divisors is an integer number (6552051211).
Almost surely, 213104102421 is an apocalyptic number.
It is an amenable number.
13104102421 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104102421 is an equidigital number, since it uses as much as digits as its factorization.
13104102421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 13104102421 its reverse (12420140131), we get a palindrome (25524242552).
The spelling of 13104102421 in words is "thirteen billion, one hundred four million, one hundred two thousand, four hundred twenty-one".
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