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13104114431 is a prime number
BaseRepresentation
bin11000011010001000…
…01110101011111111
31020211020200222121112
430031010032223333
5203314123130211
610004150352235
7642506064152
oct141504165377
936736628545
1013104114431
115614a27141
12265865b67b
13130ab26185
148c450bc99
1551a66a88b
hex30d10eaff

13104114431 has 2 divisors, whose sum is σ = 13104114432. Its totient is φ = 13104114430.

The previous prime is 13104114391. The next prime is 13104114467. The reversal of 13104114431 is 13441140131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13104114431 is a prime.

It is a super-2 number, since 2×131041144312 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104114397 and 13104114406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104114931) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552057215 + 6552057216.

It is an arithmetic number, because the mean of its divisors is an integer number (6552057216).

Almost surely, 213104114431 is an apocalyptic number.

13104114431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104114431 is an equidigital number, since it uses as much as digits as its factorization.

13104114431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13104114431 its reverse (13441140131), we get a palindrome (26545254562).

The spelling of 13104114431 in words is "thirteen billion, one hundred four million, one hundred fourteen thousand, four hundred thirty-one".