1310412001122 has 24 divisors (see below), whose sum is σ = 3244829717376. Its totient is φ = 374403428856.

The previous prime is 1310412001039. The next prime is 1310412001219. The reversal of 1310412001122 is 2211002140131.

1310412001122 is a `hidden beast` number, since 1 + 310 + 41 + 200 + 112 + 2 = 666.

It is a super-2 number, since 2×1310412001122² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1310412001095 and 1310412001104.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5200047498 + ... + 5200047749.

It is an arithmetic number, because the mean of its divisors is an integer number (135201238224).

Almost surely, 2^{1310412001122} is an apocalyptic number.

1310412001122 is an abundant number, since it is smaller than the sum of its proper divisors (1934417716254).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310412001122 is a wasteful number, since it uses less digits than its factorization.

1310412001122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10400095262 (or 10400095259 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 1310412001122 its reverse (2211002140131), we get a palindrome (3521414141253).

The spelling of 1310412001122 in words is "one trillion, three hundred ten billion, four hundred twelve million, one thousand, one hundred twenty-two".