Base | Representation |
---|---|
bin | 10011000100011010110… |
… | …001100000100011110111 |
3 | 11122021102000112012110111 |
4 | 103010122301200203313 |
5 | 132432212014230234 |
6 | 2441555044203451 |
7 | 163450200004453 |
oct | 23043261404367 |
9 | 4567360465414 |
10 | 1310414211319 |
11 | 46581a729304 |
12 | 191b73099587 |
13 | 96757860865 |
14 | 475d2731663 |
15 | 24148352664 |
hex | 1311ac608f7 |
1310414211319 has 2 divisors, whose sum is σ = 1310414211320. Its totient is φ = 1310414211318.
The previous prime is 1310414211179. The next prime is 1310414211331. The reversal of 1310414211319 is 9131124140131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310414211319 is a prime.
It is a super-2 number, since 2×13104142113192 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310414211619) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655207105659 + 655207105660.
It is an arithmetic number, because the mean of its divisors is an integer number (655207105660).
Almost surely, 21310414211319 is an apocalyptic number.
1310414211319 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310414211319 is an equidigital number, since it uses as much as digits as its factorization.
1310414211319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 1310414211319 in words is "one trillion, three hundred ten billion, four hundred fourteen million, two hundred eleven thousand, three hundred nineteen".
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