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131041451 is a prime number
BaseRepresentation
bin1111100111110…
…00100010101011
3100010120121002002
413303320202223
5232021311301
621000401215
73150556022
oct763704253
9303517062
10131041451
1167a73422
1237a7620b
13211c1828
14135918b9
15b78716b
hex7cf88ab

131041451 has 2 divisors, whose sum is σ = 131041452. Its totient is φ = 131041450.

The previous prime is 131041447. The next prime is 131041483. The reversal of 131041451 is 154140131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131041451 - 22 = 131041447 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131041951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65520725 + 65520726.

It is an arithmetic number, because the mean of its divisors is an integer number (65520726).

Almost surely, 2131041451 is an apocalyptic number.

131041451 is a deficient number, since it is larger than the sum of its proper divisors (1).

131041451 is an equidigital number, since it uses as much as digits as its factorization.

131041451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 131041451 is about 11447.3337943820. Note that the first 3 decimals coincide. The cubic root of 131041451 is about 507.9288694401.

Adding to 131041451 its reverse (154140131), we get a palindrome (285181582).

The spelling of 131041451 in words is "one hundred thirty-one million, forty-one thousand, four hundred fifty-one".