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13104166041353 is a prime number
BaseRepresentation
bin1011111010110000110100…
…1010010111011100001001
31201101202010212021200220002
42332230031022113130021
53204144313001310403
643511545404212345
72521513310344142
oct276541512273411
951352125250802
1013104166041353
1141a249a118382
12157781283a0b5
13740943613a8a
1433436049cac9
1517ad094e4188
hexbeb0d297709

13104166041353 has 2 divisors, whose sum is σ = 13104166041354. Its totient is φ = 13104166041352.

The previous prime is 13104166041349. The next prime is 13104166041371. The reversal of 13104166041353 is 35314066140131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7810057443904 + 5294108597449 = 2794648^2 + 2300893^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104166041353 - 22 = 13104166041349 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13104166044353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552083020676 + 6552083020677.

It is an arithmetic number, because the mean of its divisors is an integer number (6552083020677).

Almost surely, 213104166041353 is an apocalyptic number.

It is an amenable number.

13104166041353 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104166041353 is an equidigital number, since it uses as much as digits as its factorization.

13104166041353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 38.

The spelling of 13104166041353 in words is "thirteen trillion, one hundred four billion, one hundred sixty-six million, forty-one thousand, three hundred fifty-three".