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1310421211357 is a prime number
BaseRepresentation
bin10011000100011011001…
…100001101100011011101
311122021102111200211201011
4103010123030031203131
5132432220312230412
62441555454215221
7163450313340646
oct23043314154335
94567374624634
101310421211357
1146582367a565
12191b754b4511
1396759141aab
14475d36346cd
1524148c867a7
hex1311b30d8dd

1310421211357 has 2 divisors, whose sum is σ = 1310421211358. Its totient is φ = 1310421211356.

The previous prime is 1310421211327. The next prime is 1310421211391. The reversal of 1310421211357 is 7531121240131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1139611760676 + 170809450681 = 1067526^2 + 413291^2 .

It is an emirp because it is prime and its reverse (7531121240131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310421211357 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310421211327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655210605678 + 655210605679.

It is an arithmetic number, because the mean of its divisors is an integer number (655210605679).

Almost surely, 21310421211357 is an apocalyptic number.

It is an amenable number.

1310421211357 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310421211357 is an equidigital number, since it uses as much as digits as its factorization.

1310421211357 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 31.

Adding to 1310421211357 its reverse (7531121240131), we get a palindrome (8841542451488).

The spelling of 1310421211357 in words is "one trillion, three hundred ten billion, four hundred twenty-one million, two hundred eleven thousand, three hundred fifty-seven".