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1310430051157 is a prime number
BaseRepresentation
bin10011000100011011101…
…101111011101101010101
311122021110010022221122011
4103010123231323231111
5132432230043114112
62442000411504221
7163450451435653
oct23043355735525
94567403287564
101310430051157
11465828667a87
12191b78458071
139675ac18546
14475d4895dd3
1524149930aa7
hex1311bb7bb55

1310430051157 has 2 divisors, whose sum is σ = 1310430051158. Its totient is φ = 1310430051156.

The previous prime is 1310430051137. The next prime is 1310430051163. The reversal of 1310430051157 is 7511500340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 941299682436 + 369130368721 = 970206^2 + 607561^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310430051157 - 215 = 1310430018389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310430051137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655215025578 + 655215025579.

It is an arithmetic number, because the mean of its divisors is an integer number (655215025579).

Almost surely, 21310430051157 is an apocalyptic number.

It is an amenable number.

1310430051157 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310430051157 is an equidigital number, since it uses as much as digits as its factorization.

1310430051157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6300, while the sum is 31.

Adding to 1310430051157 its reverse (7511500340131), we get a palindrome (8821930391288).

The spelling of 1310430051157 in words is "one trillion, three hundred ten billion, four hundred thirty million, fifty-one thousand, one hundred fifty-seven".