13104304000422 has 16 divisors (see below), whose sum is σ = 26847842342832. Its totient is φ = 4261562276480.

The previous prime is 13104304000421. The next prime is 13104304000433. The reversal of 13104304000422 is 22400040340131.

It is a junction number, because it is equal to n+sod(n) for n = 13104304000392 and 13104304000401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104304000421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26634763983 + ... + 26634764474.

It is an arithmetic number, because the mean of its divisors is an integer number (1677990146427).

Almost surely, 2^{13104304000422} is an apocalyptic number.

13104304000422 is an abundant number, since it is smaller than the sum of its proper divisors (13743538342410).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104304000422 is a wasteful number, since it uses less digits than its factorization.

13104304000422 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53269528503.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13104304000422 its reverse (22400040340131), we get a palindrome (35504344340553).

The spelling of 13104304000422 in words is "thirteen trillion, one hundred four billion, three hundred four million, four hundred twenty-two", and thus it is an aban number.