Base | Representation |
---|---|
bin | 10011000100011011110… |
… | …001100011111000011111 |
3 | 11122021110012010021010212 |
4 | 103010123301203320133 |
5 | 132432230314032033 |
6 | 2442000444123035 |
7 | 163450462506344 |
oct | 23043361437037 |
9 | 4567405107125 |
10 | 1310431002143 |
11 | 46582915751a |
12 | 191b7883647b |
13 | 9675b18c363 |
14 | 475d4a627cb |
15 | 24149a6c748 |
hex | 1311bc63e1f |
1310431002143 has 2 divisors, whose sum is σ = 1310431002144. Its totient is φ = 1310431002142.
The previous prime is 1310431002113. The next prime is 1310431002157. The reversal of 1310431002143 is 3412001340131.
It is a strong prime.
It is an emirp because it is prime and its reverse (3412001340131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1310431002143 - 210 = 1310431001119 is a prime.
It is a super-2 number, since 2×13104310021432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310431002113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655215501071 + 655215501072.
It is an arithmetic number, because the mean of its divisors is an integer number (655215501072).
Almost surely, 21310431002143 is an apocalyptic number.
1310431002143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310431002143 is an equidigital number, since it uses as much as digits as its factorization.
1310431002143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 1310431002143 its reverse (3412001340131), we get a palindrome (4722432342274).
The spelling of 1310431002143 in words is "one trillion, three hundred ten billion, four hundred thirty-one million, two thousand, one hundred forty-three".
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