Search a number
-
+
1310432401153 is a prime number
BaseRepresentation
bin10011000100011011110…
…110111001011100000001
311122021110021202100020001
4103010123312321130001
5132432231143314103
62442000534120001
7163450510424161
oct23043366713401
94567407670201
101310432401153
11465829a22627
12191b791b0001
139675b55c085
14475d4d085a1
1524149c4701d
hex1311bdb9701

1310432401153 has 2 divisors, whose sum is σ = 1310432401154. Its totient is φ = 1310432401152.

The previous prime is 1310432401141. The next prime is 1310432401199. The reversal of 1310432401153 is 3511042340131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1172904162049 + 137528239104 = 1083007^2 + 370848^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310432401153 is a prime.

It is not a weakly prime, because it can be changed into another prime (1310432401253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655216200576 + 655216200577.

It is an arithmetic number, because the mean of its divisors is an integer number (655216200577).

Almost surely, 21310432401153 is an apocalyptic number.

It is an amenable number.

1310432401153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310432401153 is an equidigital number, since it uses as much as digits as its factorization.

1310432401153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 1310432401153 its reverse (3511042340131), we get a palindrome (4821474741284).

The spelling of 1310432401153 in words is "one trillion, three hundred ten billion, four hundred thirty-two million, four hundred one thousand, one hundred fifty-three".