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1310432401141 is a prime number
BaseRepresentation
bin10011000100011011110…
…110111001011011110101
311122021110021202100012121
4103010123312321123311
5132432231143314031
62442000534115541
7163450510424143
oct23043366713365
94567407670177
101310432401141
11465829a22616
12191b791abbb1
139675b55c076
14475d4d08593
1524149c47011
hex1311bdb96f5

1310432401141 has 2 divisors, whose sum is σ = 1310432401142. Its totient is φ = 1310432401140.

The previous prime is 1310432401139. The next prime is 1310432401153. The reversal of 1310432401141 is 1411042340131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 934760248900 + 375672152241 = 966830^2 + 612921^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310432401141 - 21 = 1310432401139 is a prime.

Together with 1310432401139, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310432401441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655216200570 + 655216200571.

It is an arithmetic number, because the mean of its divisors is an integer number (655216200571).

Almost surely, 21310432401141 is an apocalyptic number.

It is an amenable number.

1310432401141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310432401141 is an equidigital number, since it uses as much as digits as its factorization.

1310432401141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1310432401141 its reverse (1411042340131), we get a palindrome (2721474741272).

The spelling of 1310432401141 in words is "one trillion, three hundred ten billion, four hundred thirty-two million, four hundred one thousand, one hundred forty-one".