13104325400124 has 192 divisors, whose sum is σ = 35386426607616. Its totient is φ = 3697135681536.

The previous prime is 13104325400077. The next prime is 13104325400137. The reversal of 13104325400124 is 42100452340131.

It is a junction number, because it is equal to n+sod(n) for n = 13104325400091 and 13104325400100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2157797952 + ... + 2157804024.

It is an arithmetic number, because the mean of its divisors is an integer number (184304305248).

Almost surely, 2^{13104325400124} is an apocalyptic number.

13104325400124 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13104325400124, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17693213303808).

13104325400124 is an abundant number, since it is smaller than the sum of its proper divisors (22282101207492).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104325400124 is a wasteful number, since it uses less digits than its factorization.

13104325400124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7244 (or 7242 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 13104325400124 its reverse (42100452340131), we get a palindrome (55204777740255).

The spelling of 13104325400124 in words is "thirteen trillion, one hundred four billion, three hundred twenty-five million, four hundred thousand, one hundred twenty-four".