Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …1010111011110001000111 |
3 | 1201101202120120020222010211 |
4 | 2332230113022323301013 |
5 | 3204200133443243221 |
6 | 43512014203300251 |
7 | 2521520416553464 |
oct | 276542712736107 |
9 | 51352516228124 |
10 | 13104333962311 |
11 | 41a257598a929 |
12 | 157785ab1a687 |
13 | 74096c3489a7 |
14 | 3343788d066b |
15 | 17ad191136e1 |
hex | beb172bbc47 |
13104333962311 has 2 divisors, whose sum is σ = 13104333962312. Its totient is φ = 13104333962310.
The previous prime is 13104333962281. The next prime is 13104333962389. The reversal of 13104333962311 is 11326933340131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13104333962311 - 215 = 13104333929543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104337962311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552166981155 + 6552166981156.
It is an arithmetic number, because the mean of its divisors is an integer number (6552166981156).
Almost surely, 213104333962311 is an apocalyptic number.
13104333962311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104333962311 is an equidigital number, since it uses as much as digits as its factorization.
13104333962311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976, while the sum is 40.
The spelling of 13104333962311 in words is "thirteen trillion, one hundred four billion, three hundred thirty-three million, nine hundred sixty-two thousand, three hundred eleven".
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