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13104334209949 is a prime number
BaseRepresentation
bin1011111010110001011100…
…1011111000001110011101
31201101202120120201112211121
42332230113023320032131
53204200134024204244
643512014212450541
72521520421634453
oct276542713701635
951352516645747
1013104334209949
1141a2576039994
12157785b019a51
1374096c404618
143343789569d3
1517ad19161c84
hexbeb172f839d

13104334209949 has 2 divisors, whose sum is σ = 13104334209950. Its totient is φ = 13104334209948.

The previous prime is 13104334209929. The next prime is 13104334209959. The reversal of 13104334209949 is 94990243340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7998460704025 + 5105873505924 = 2828155^2 + 2259618^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104334209949 - 225 = 13104300655517 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104334209896 and 13104334209905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104334209929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552167104974 + 6552167104975.

It is an arithmetic number, because the mean of its divisors is an integer number (6552167104975).

Almost surely, 213104334209949 is an apocalyptic number.

It is an amenable number.

13104334209949 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104334209949 is an equidigital number, since it uses as much as digits as its factorization.

13104334209949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2519424, while the sum is 52.

The spelling of 13104334209949 in words is "thirteen trillion, one hundred four billion, three hundred thirty-four million, two hundred nine thousand, nine hundred forty-nine".