Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …1011111000010010100101 |
3 | 1201101202120120201120012101 |
4 | 2332230113023320102211 |
5 | 3204200134024211323 |
6 | 43512014212452101 |
7 | 2521520421635311 |
oct | 276542713702245 |
9 | 51352516646171 |
10 | 13104334210213 |
11 | 41a257603a104 |
12 | 157785b01a031 |
13 | 74096c40478c |
14 | 334378956b41 |
15 | 17ad19161dad |
hex | beb172f84a5 |
13104334210213 has 2 divisors, whose sum is σ = 13104334210214. Its totient is φ = 13104334210212.
The previous prime is 13104334210147. The next prime is 13104334210223. The reversal of 13104334210213 is 31201243340131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13007549133604 + 96785076609 = 3606598^2 + 311103^2 .
It is a cyclic number.
It is not a de Polignac number, because 13104334210213 - 237 = 12966895256741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104334210223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552167105106 + 6552167105107.
It is an arithmetic number, because the mean of its divisors is an integer number (6552167105107).
Almost surely, 213104334210213 is an apocalyptic number.
It is an amenable number.
13104334210213 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104334210213 is an equidigital number, since it uses as much as digits as its factorization.
13104334210213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13104334210213 its reverse (31201243340131), we get a palindrome (44305577550344).
The spelling of 13104334210213 in words is "thirteen trillion, one hundred four billion, three hundred thirty-four million, two hundred ten thousand, two hundred thirteen".
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