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13104334224431 is a prime number
BaseRepresentation
bin1011111010110001011100…
…1011111011110000101111
31201101202120120202021200222
42332230113023323300233
53204200134030140211
643512014213041555
72521520422024622
oct276542713736057
951352516667628
1013104334224431
1141a257604985a
12157785b0262bb
1374096c40b0a8
1433437895bdb9
1517ad191661db
hexbeb172fbc2f

13104334224431 has 2 divisors, whose sum is σ = 13104334224432. Its totient is φ = 13104334224430.

The previous prime is 13104334224409. The next prime is 13104334224467. The reversal of 13104334224431 is 13442243340131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13104334224431 is a prime.

It is a super-2 number, since 2×131043342244312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13104334224391 and 13104334224400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104334224031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552167112215 + 6552167112216.

It is an arithmetic number, because the mean of its divisors is an integer number (6552167112216).

Almost surely, 213104334224431 is an apocalyptic number.

13104334224431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104334224431 is an equidigital number, since it uses as much as digits as its factorization.

13104334224431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 13104334224431 its reverse (13442243340131), we get a palindrome (26546577564562).

The spelling of 13104334224431 in words is "thirteen trillion, one hundred four billion, three hundred thirty-four million, two hundred twenty-four thousand, four hundred thirty-one".